2x+5=8+2(x-4)-3^2-x

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Solution for 2x+5=8+2(x-4)-3^2-x equation: 



2x+5=8+2(x-4)-3^2-x

We move all terms to the left:

2x+5-(8+2(x-4)-3^2-x)=0



We calculate terms in parentheses: -(8+2(x-4)-3^2-x), so:

8+2(x-4)-3^2-x

determiningTheFunctionDomain
2(x-4)-x+8-3^2

We add all the numbers together, and all the variables

-1x+2(x-4)-1

We multiply parentheses

-1x+2x-8-1

We add all the numbers together, and all the variables

x-9

Back to the equation:

-(x-9)



We get rid of parentheses

2x-x+9+5=0

We add all the numbers together, and all the variables

x+14=0

We move all terms containing x to the left, all other terms to the right

x=-14

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